The polynomial remainder theorem allows us to calculate the remainder when a polynomial is divided by a linear polynomial:
The remainder of f(x) divided by (x-k) equals f(k).
Thus
f(x)=x^3+3x^2-10x-4 divided by x-3
gives a remainder of
f(3)=27+3(9)-10(3)-4=27+27-30-4=20
Therefore the remainder required is 20.
9514 1404 393
Answer:
n = 5/2
Step-by-step explanation:
Given
5/2(4n -10) +4 = 2/3(6n -9)
5(2n -5) +4 = 2(2n -3) . . . . . . . simplify a bit
10n -25 +4 = 4n -6 . . . . . . . . . eliminate parentheses
6n = 15 . . . . . . . . . . . . . . . . . . . add 21-4n
n = 15/6 = 5/2
The value of n that makes the equation true is n = 5/2 = 2.5.
Decimals from 7.0 to 8.4 with an interval of 0.2 between each pair of decimals
We start with 7.0 and keep adding 0.2 till we get 8.4
7.0 + 0.2 = 7.2
7.2 + 0.2 = 7.4
7.4 + 0.2 = 7.6
7.6 + 0.2 = 7.8
7.8 + 0.2 = 8.0
8.0 + 0.2 = 8.2
8.2 + 0.2 = 8.4
So, the decimals from 7.0 to 8.4 with an interval of 0.2 are
7.2, 7.4, 7.6, 7.8, 8.0, 8.2
C. Y=12
There’s no x variable
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