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3 years ago

The magnetic strips on a credit card can become demagnetized. What type of magnet are they?

1 answer:

3 0

A magnetic stripe card is a type of card capable of storing data by modifying the magnetism of tiny iron<span>-based magnetic particles on a band of magnetic material on the card.</span>

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What type of change is wood to wood chip?

Vanyuwa [196]

Answer:

irriversible change.....

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3 years ago

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What was the largest group in the colonies in the year leading up to the American revoulation

Degger [83]

Answer: The English origin was the largest

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2 years ago

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Photon Lighting Company determines that the supply and demand functions for its most popular lamp are as follows: S(p) = 400 - 4

torisob [31]

Answer: The correct answer is (C).

Explanation:

Supply function:

$S(p)=400-4p+0.00002p^4$

Demand function:

$D(p)=2800-0.0012p^3$

S(p)=D(p), price for which supply is equal to demand:

$S(p)=D(p)=400-4p+0.00002p^4=2800-0.0012p^3$

After solving this above equation graphically, we will get the values of p.

1) p =96.236

2) p=( -118.258)

We will reject the negative value of p.

So, the value of p that price for which the supply equals the demand is $ 96.236 $\approx$ $96.24. Hence, the correct answer is option (C).

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3 years ago

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the moon revolves around the earth in a nearly circular orbit kept by gravitational force exerted by the earth work done will be

rodikova [14]

Answer:

Zero because the applied force is perpendicular to the motion of the object.

No work is done on an object moving is a circular path about a central attractive force.

Any work done in such a case would result in a change in the orbit.

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3 years ago

A capacitance C and an inductance L are operated at the same angular frequency.

Levart [38]

A) $\omega = \frac{1}{\sqrt{LC}}$

The magnitude of the capacitive reactance is given by

$X_C = \frac{1}{\omega C}$

where

$\omega$ is the angular frequency

C is the capacitance

While the magnitude of the inductive capacitance is given by

$X_L = \omega L$

where L is the inductance.

Since we want the two reactances to be equal, we have

$X_C = X_L$

So we find

$\frac{1}{\omega C}= \omega L\\\omega^2 = \frac{1}{LC}\\\omega = \frac{1}{\sqrt{LC}}$

B) 7449 rad/s

In this case, we have

$L=5.30 mH = 5.3\cdot 10^{-3}H$ is the inductance

$C= 3.40 \mu F= 3.40 \cdot 10^{-6}F$ is the capacitance

Therefore, substituting in the formula for the angular frequency, we find

$\omega=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{(5.30\cdot 10^{-3}H)(3.40\cdot 10^{-6} F)}}=7449 rad/s$

C) $39.5 \Omega$

Now we can us the formulas of the reactances written in part A). We have:

- Capacitive reactance:

$X_C = \frac{1}{\omega C}=\frac{1}{(7449 rad/s)(3.40\cdot 10^{-6}F)}=39.5 \Omega$

- Inductive reactance:

$X_L = \omega L=(7449 rad/s)(5.30\cdot 10^{-3}H)=39.5 \Omega$

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3 years ago