Answer:
Incomplete question, check attachment for the graph needed to solve problem.
A 8.1nm........
Explanation:
Electric Field is given as
E=V/d
Where V is voltage
And d is the distance apart
E is the electric field
The voltage V just before action of potential is -70mV,
The value d=8.1nm
d=8.1×10^-9m
E=V/d
E=-70×10^-3/8.1×10^-9
E=-8.6×10^6 N/C
Then the magnitude of the electric field is 8.6×10^6N/C
The final velocity is 1.37 m/s east
Explanation:
We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.
So we can write:
where:
is the mass of the first train
is the initial velocity of the first train (we take east as positive direction)
is the mass of the second train
is the initial velocity of the second train
is the final combined velocity of the two trains
Re-arranging the equation and substituting the values, we find:
And the positive sign indicates their final direction is east.
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Answer:
Energy transferred = 28.8 Joules.
1. Energy transferred = 144 Joules.
2. The unit of potential difference, volts can also be described as Joules per Coulombs.
3. Current, I = 6.945 Amperes.
Explanation:
<u>Part A.</u>
Given the following data;
Current, I = 1.2A
Time, t = 2 minutes
Potential difference, V = 12 volts.
To find the energy transfered;
Energy transferred = charge moved * potential difference
E = Q * V
Substituting into the equation, we have;
Energy transferred = (1.2 * 2) * 12
Energy transferred = 2.4 * 12
Energy transferred = 28.8 Joules.
<u>Part B.</u>
1. <em><u>Given the following data;</u></em>
Charge, Q = 24C
Potential difference = 6V
To find the energy transferred;
E = Q * V
Substituting into the equation, we have;
E = 24 * 6
E = 144 Joules.
2. Since we know that, Energy transferred = charge moved * potential difference
The units of energy is Joules while the unit of the quantity of charge moved is Coulomb.
Therefore, the unit of potential difference becomes Joules per Coulomb.
3. <em><u>Given the following data;</u></em>
Potential difference = 18V
Energy transferred = 500J
Time, t = 4 minutes.
To find the current;
E = Q * V
Substituting into the equation, we have;
500 = Q*18
Q = 500/18
Q = 27.78C
But, Charge moved (Q) = current (I) * time (t)
Current, I = Q/t
Substituting into the equation, we have;
Current, I = 27.78/4
Current, I = 6.945 Amperes..
Forward thrust has positive values and reverse thrust has negative values.
Thrust is a sudden push or pull in a certain direction.
a)
Flight speed u = 150 km/h
1 km/h = km/s
therefore, 150 km/h = 41.67 km / s
The thrust force represents the horizontal or x-component of momentum equation:
T = 50 * (150 - 41.67)
T = 5416.67 N
Therefore, the value of forward thrust is 5416.67 N.
b)
Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,
thus thrust equation is:
T = 50 * (0 - 41.67)
T = -2083.5 N
Therefore, the thrust force T is -2083.5 N in the reverse direction.
c)
Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because
T = 0
Therefore, there is no difference in two velocities in x direction.
The given question is incomplete, the complete question is,
"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.
a. What is the forward thrust of this engine?
b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?
c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"
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