Length = w+3
P = 2L +2W
50 = 2(w+3) + 2w
50 = 2w +6 +2w
50 = 4w +6
50-6 =4w-6
44 = 4w
44/4 = 4w/4
w = 11
l = 11+3
l = 14
50 = 2L+2W
50 = 2(14) + 2(11)
50 = 28 +22
50=50
Ok so how I get taught to do this is you need to know the basics of algebra if you know that then respond and I’ll tell you how to solve that
23x-13=2(x+2)
First you would distribute the 2 into the parenthesis
It will look like this after: 23x-13=2x+4
Then you would subtract 2x on both sides because u have to get the x's on one side
It will look like this after:21x-13=4
Then you would add 13 to both sides
It will look like this after: 21x=17
Then you would divide 21 on both sides
Your final product is 21/17
Answer: x=7 and AC = 44 unuts.
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other. (i)
Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.
BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6
Using (i)
Now , AE = 4(7)-6 = 28-6 = 22
AC =2 AE = 2 (22) =44 units.
Hence, x=7 and AC = 44 unuts.
