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kramer
3 years ago
8

What is the answer for 23x9+(91+7)

Mathematics
2 answers:
mestny [16]3 years ago
3 0

Answer:

305

Step-by-step explanation:

23×9+98

207+98

305

Luden [163]3 years ago
3 0
91+7=98 23x9=207 207+98=305
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Suppose a man offered to work for 30 days at the following salary: one cent for the first day two cents for the second day four
Ivahew [28]
It would be to little because it would only be 30 cents
8 0
3 years ago
Which of the following best describes the equation below?
Reika [66]
4(x + 9) + 5x = 9x - 36

=> 4x + 36 + 5x = 9x - 36

=> 9x + 36 = 9x - 36

=> 9x - 9x = -36 - 36

=> 0 = -72

You can see that the equation doesn't hold true.

So there is no solution for this equation.

Answer is C. no real solutions
5 0
3 years ago
A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem
borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

Recall that

D = 17000 at x = 3

So, we have

17000 = 1400√(25-3²) + C

Evaluate

17000 = 5600 + C

Solve for C

C = 17000 - 5600

So, we have

C = 11400

Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400

Read more about demand function at

brainly.com/question/24384825

#SPJ1

3 0
1 year ago
Solve the variable in the following proportion. 3.6/y=1.2/2
Molodets [167]
Hello : 
<span>3.6/y=1.2/2
1.2 y = 2(3.6)
y = 2(3.6)/1.2
y=6</span>
7 0
3 years ago
What is one of the solutions to the following equations? y2+x2=53<br> Y-x=5
Olenka [21]
(1)  y² + x² = 53
(2)  y - x = 5 ⇒ y = x + 5

subtitute (2) to (1)

(x + 5)² + x² = 53      |use (a + b)² = a² + 2ab + b²

x² + 2x·5 + 5² + x² = 53

2x² + 10x + 25 = 53     |subtract 53 from both sides

2x² + 10x - 28 =0     |divide both sides by 2

x² + 5x - 14 = 0

x² - 2x+ 7x - 14 = 0

x(x - 2) + 7(x - 2) = 0

(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7

subtitute the values of y to (2)

for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3

Answer: x = 2 and y = 7 or x = -7 and y = 3
4 0
3 years ago
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