We are given the equation of a line
y = -2x + 1
We have to find the value of y at three different values of x i.e. at x =0, -3 and 1
In order to find the value of y at any given x, simply replace x by that number.
So, for x=0, we will replace x by 0 to find the value of y. So y will be:
y = -2(0) + 1
y = 1
This can be expressed as an ordered pair as (0,1)
Similarly for x=-3, we get:
y = -2(-3) + 1 = 6 + 1
y = 7
This can be expressed as an ordered pair as (-3, 7)
And, finally for x=1, we get:
y= -2(1) + 1 = -2 + 1
y= -1
This can be expressed as an ordered pair as (-1, -1)
Answer: y≤0
Step-by-step explanation:
Looking at the question, I'm assuming the equation is
.
To find the range if this equation, it would be best to know that the graph of a square root looks like. Knowing that x=-5, the graph starts at -5 and then increases slowly to the right. Since there are no restrictions to this equation, the graph goes towards infinity.
The graph represents a parabola and a parabola is maximum or minimum at its vertex . So we need to check the graph , and find the point where the graph is maximum or minimum. And from the given graph , we can say that it is a downward up parabola which is minimum at its vertex . And the minimum point is (1.4). So the vertex is (1,4) .
Answer:
c
Step-by-step explanation:
<em>To </em><em>find </em><em>the </em><em>midpoint</em><em> </em><em>the </em><em>formulas</em>
<em>x=</em><em>x1+</em><em>x2/</em><em>2</em><em> </em><em>and </em><em>y</em><em>=</em><em>y1+</em><em>y2/</em><em>2</em><em> </em><em>are </em><em>used </em>
<em>in </em><em>this </em><em>case </em><em>x1 </em><em>is </em><em>5</em><em>,</em><em>x2 </em><em>is </em><em>5</em><em>,</em><em>y1 </em><em>is </em><em>4</em><em> </em><em>and </em><em>y2 </em><em>is </em><em>-</em><em>3</em>
<em>therefore</em>
<em>x=</em><em>5</em><em>+</em><em>5</em><em>/</em><em>2</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<em> </em><em> </em><em>=</em><em>1</em><em>0</em><em>/</em><em>2</em>
<em> </em><em> </em><em>=</em><em>5</em>
<em>y=</em><em>4</em><em>+</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em>
<em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>2</em>