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3 years ago

When 2 less than 3 lots of a number is doubled the result is 5

Mathematics

2 answers:

Vitek1552 [10]3 years ago

4 0

Can you rephrase it? (maybe write it out in numbers?)

Misha Larkins [42]3 years ago

4 0

Let the number be n

the first half (2 less than 3 lots of a number) is in brackets.
3 lots of a number is 3 x the number and 2 less than it is subtracting 2 from the product.
So 3n-2.
That whole number is doubled so the 2 is left outside the brackets so that it applies to everything inside.
2(3n-2) = 5

im not sure if you were asked to find the number but if you are then you must work in opposite operations.

First, divide both sides by 2--
3n-2 = 2.5
then add the 2 to both sides
3n = 4.5
divide both by 3 and tha'ts the answer for n but its a decimal so i doubt its asking for that

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find three consecutive numbers such that three times the first number is equal to 9 more than the sum of the other two.

Goryan [66]

Answer:

12, 13, 14

Step-by-step explanation:

Three consecutive numbers means three numbers in a row, so if n is the first number, the second number is one more than n (which is n+1) and the third number is one more than that (which is n+2)

So three times (3 x) the first number (n) is equal to (=) nine more than (9 +) the sum of the other two ( (n+1) + (n+2) )

3 times n can be written as 3n

So 3n = 9 + (n+1) + (n+2)

3n = 9 + n + 1 + n + 2

3n = 9 + 1 + 2 + n + n

3n = 12 + 2n

Subtract 2n from each side

3n - 2n = 12 + 2n - 2n

1n = 12

n = 12

So the first number is 12, the second number is 12 + 1 (13) and the third number is 12 + 2 (14)

The numbers are 12, 13, 14

Hope this helps :)

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3 years ago

How much is 74 divided by 4

exis [7]

Answer:

18.5

Step-by-step explanation:

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2 years ago

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castortr0y [4]

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2 years ago

5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

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2 years ago

Gavin drove 85 miles on 10 gallons of gas.How many miles can gavin drive on 25 gallons of gas?

bixtya [17]

Answer:

212.5 miles on 25 gallons.

Step-by-step explanation:

Set up a proportion

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85/10 = x / 25 Multiply both sides by 25

85*25 / 10 = x Simplify the left

2125 / 10 = x

x = 212.5 miles in 25 gallons.

6 0

3 years ago