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2 years ago

Need help

Mathematics

1 answer:

I am Lyosha [343]2 years ago

5 0

Answer:

see in the graph, the circle has: the centre I(3; -2)

r = 3

=> the equation: (x - 3)² + (y + 2)² = 9

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A hamster running in a wheel of radius 13 cm spins the wheel at 35 revolutions per minute.

crimeas [40]

One revolution is completed when a fixed point on the wheel travels a distance equal to the circumference of the wheel, which is 2π (13 cm) = 26π cm.

So we have

1 rev = 26π cm

1 rev = 2π rad

1 min = 60 s

(a) The angular velocity of the wheel is

(35 rev/min) * (2π rad/rev) * (1/60 min/s) = 7π/6 rad/s

or approximately 3.665 rad/s.

(b) The linear velocity is

(35 rev/min) * (26π cm/rev) * (1/60 min/s) = 91π/6 cm/s

or roughly 47.648 cm/s.

5 0

3 years ago

Doug’s family buys 7 postcards while on vacation. Each postcard costs 0.25$ including tax. How can Doug use the number line to f

larisa [96]

Answer: Total cost is $1.75

Explanation:

Since we have given that

Number of postcards bought by Doug's family= 7

Cost of each postcard including tax = $0.25

Total cost is given by

$7\times 0.25=\$1.75$

Now, we want to show this in number line :

On the number line put all the number with a difference of 0.25 and run the number line seven times and we get the answer.

Each step is of length 0.25 and there are 7 jumps to reach required answer.

So, after 7 jumps we reach at 1.75 which is the required answer.

Hence total cost is $1.75

3 0

2 years ago

Consider this linear function:

ivanzaharov [21]

Answer:

(-8,-3)

(-4,-1)

(0,1)

(2,2)

(6,4)

Step-by-step explanation:

One by one, substitue the x values and solve for y

3 0

2 years ago

Find the image of A(-2,4) under a translation (x,y)->(x-2,y-3)

vichka [17]

Answer:

Point A would be at the coordinates, (-4, 1). Hope this helps!

4 0

1 year ago

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

3 years ago