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Mamont248 [21]
3 years ago
14

Need help

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

see in the graph, the circle has: the centre I(3; -2)

r = 3

=> the equation: (x - 3)² + (y + 2)² = 9

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Part 1) x-2y=2 ----> (2,0) and (0,-1)

Part 2) -3x+3y=7 ----> (-7/3,0) and (0,7/3)

Part 3) 7x-y=21 ----> (3,0) and (0,-21)

Part 4) 3x-5y=-20 ----> (-20/3,0) and (0,4)

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

The x-intercept is the value of x when the value of y is equal to zero

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x-2y=2

1) <u><em>Find the x-intercept</em></u>

For y=0

x-2(0)=2\\x=2

the x-intercept is (2,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

0-2y=2\\y=-1

the y-intercept is (0,-1)

Part 2) we have

-3x+3y=7

1) <u><em>Find the x-intercept</em></u>

For y=0

-3x+3(0)=7\\x=-\frac{7}{3}

the x-intercept is (-7/3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

-3(0)+3y=7\\y=\frac{7}{3}

the y-intercept is (0,7/3)

Part 3) we have

7x-y=21

1) <u><em>Find the x-intercept</em></u>

For y=0

7x-(0)=21\\x=3

the x-intercept is (3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

7(0)-y=21\\y=-21

the y-intercept is (0,-21)

Part 4) we have

3x-5y=-20

1) <u><em>Find the x-intercept</em></u>

For y=0

3x-5(0)=-20\\x=-\frac{20}{3}

the x-intercept is (-20/3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

3(0)-5y=-20\\y=4

the y-intercept is (0,4)

8 0
3 years ago
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