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Kisachek [45]
2 years ago
10

PLEASE ANSWER ASAPPPP I WILL MARK BRAINLY

Mathematics
2 answers:
drek231 [11]2 years ago
5 0

Answer:

1

Step-by-step explanation:

the two last answers are obviously wrong (if you want I can explain it to you in the comments)

the second one is mathematically wrong

So I am pretty sure the correct answer is the first one

anastassius [24]2 years ago
4 0

Answer:

The answer is option A.

7( \frac{x}{8} ) +  \frac{3}{4}  =  - 6

Hope this helps you

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Which is the completely factored from of xy^3-x^3y
Oksanka [162]

Answer:

xy(y+x)(y-x)

Step-by-step explanation:

To factor the expression, remove the greatest common factor or GCF from each term. Both terms share in common xy. The expression becomes:

xy^3-x^3y\\xy(y^2-x^2)

What remains in the parenthesis is a different of perfect squares. Factor the difference of perfect squares into two binomials of the form (x+a)(x-a) where a is the square root of (x^2-a^2).

So the expression becomes:

xy(y^2-x^2)\\xy(y+x)(y-x)

7 0
3 years ago
ms D ARRIVED AT SCHOOL AT 7:30 AM, SHE SPENT 35 MINUTES AT THE DINNER WITH A FRIEND IT TAKES HER 15 MINUTES TO GET TO SCHOOL WHA
Effectus [21]

Answer:

Ms D left at 6:40 AM

Step-by-step explanation:

Given:

MS D arrived at school at 7:30 AM

time spent for dinner = 35 mins

Time taken to to go to school = 15 mins

We will first find the Total time taken after leaving.

Total time taken can be calculated by adding time spent for dinner and Time taken to to go to school.

Total time taken after leaving = time spent for dinner + Time taken to to go to school = 35 +15 = 50 mins

MS D arrived at school at 7:30 AM.

Hence Time Ms D left  = Time She arrive at school - Total time taken after leaving = 7 hrs 30 min - 50 mins = 6 hrs 40 mins.

Hence Ms D left at 6:40 AM.

6 0
2 years ago
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