1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Strike441 [17]
2 years ago
9

Can I get some help on 2,4,20,40, and 50 please

Mathematics
1 answer:
scoundrel [369]2 years ago
5 0

Answer:

2. power

4. tenth

20. hundred-thousandth

40. 5.063

50. 67/10

Step-by-step explanation:

20. If the underlined digit is the zero, the answer is "hundred-thousandth." It's hard to tell from the picture if zero is the underlined digit.

40. 5 and 63/1000 = 5 + 63/1000 = 5 + 0.063 = 5.063

50. 6.700 = 6700/1000 = 67/10

You might be interested in
Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit
GaryK [48]
Answer: x = 2921, y = 579

Step-by-Step Explanation:

I am assuming that we just have to Solve for ‘x’ and ‘y’.

‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles

=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)

Adding Eq. 1 and Eq. 2, we get :-

2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921

Therefore, x = 2921

Substitute value of ‘x’ in Eq. 1 :-

x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579

Therefore, y = 579

Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579
6 0
1 year ago
D/5 = 4 please explain I do not get this. Thank you
MAXImum [283]
<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>
8 0
3 years ago
Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor
agasfer [191]

Answer:

  • E = { (4,1) , (3,2) , (2,3) , (1,4) }
  • P(E)=\frac{1}{9}
  • P(F|E)=\frac{1}{4}

Step-by-step explanation:

Let's start writing the sample space for this experiment :

S= { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event E ⇒

E : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from S ⇒

E = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate P(E) we are going to divide all the cases favorables to E over the total cases from S. We can do this because all 36 of these possible outcomes from S are equally likely. ⇒

P(E)=\frac{4}{36}=\frac{1}{9} ⇒

P(E)=\frac{1}{9}

Finally we are going to define the event F ⇒

F : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

F = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = P(A,B)

We define the conditional probability as

P(A|B)=\frac{P(A,B)}{P(B)} with P(B)>0

We need to find P(F|E) therefore we can apply the conditional probability equation :

P(F|E)=\frac{P(F,E)}{P(E)}   (I)

We calculate P(E)=\frac{1}{9} at the beginning of the question. We only need P(F,E).

Looking at the sets E and F we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

P(F,E)=\frac{1}{36}

Replacing both probabilities calculated in (I) :

P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25

We find out that P(F|E)=\frac{1}{4}=0.25

6 0
3 years ago
The price of a European tour includes stopovers at five cities to be selected from 15 cities. In how many ways can a traveler pl
xeze [42]

Answer:

The traveler can plan such a tour in 3003 ways.

Step-by-step explanation:

The order that the cities are chosen is not important, since it is chosen by the company and not by the traveler. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, we have that:

Combinations of 5 cities from a set of 15. So

C_{15,5} = \frac{15!}{5!10!} = 3003

The traveler can plan such a tour in 3003 ways.

4 0
3 years ago
Does anyone know this?
Natalija [7]

it is 24 vjsnvfvfjobbjgbnjg ngnbb

7 0
3 years ago
Other questions:
  • Coach Henderson had 16 gallons of paint to use an equal amount of paint each five days how many gallons do you use in each day
    11·1 answer
  • Which statement is true about the reflectional symmetry of a regular heptagon? Check all that apply
    13·2 answers
  • Can I get the answer please. If you get it right, the reward is a BRAINLIEST
    15·1 answer
  • After 1 month your $120 becomes $121.20. what is the yearly interest rate? ​
    7·1 answer
  • 8-2x=-4x+4<br> answer help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    13·2 answers
  • Find the length of the missing sides. Be sure to select one answer for x and for y
    14·1 answer
  • To find the quotient of 4 ÷ <br> 1<br> 8<br> , count the number of
    5·1 answer
  • How do you find the height of a cylinder when given the surface area and the diameter?
    13·1 answer
  • 6-<br> 9<br> L-<br> 5<br> -5<br> 4<br> -3<br> 3<br> у<br> X<br> :9<br> Howa urah puy
    7·1 answer
  • Just carpet has eight different quality grades of carpeting. Three types are being selected for a corporate test on durability.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!