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2 years ago

Can I get some help on 2,4,20,40, and 50 please

Mathematics

1 answer:

scoundrel [369]2 years ago

5 0

Answer:

2. power

4. tenth

20. hundred-thousandth

40. 5.063

50. 67/10

Step-by-step explanation:

20. If the underlined digit is the zero, the answer is "hundred-thousandth." It's hard to tell from the picture if zero is the underlined digit.

40. 5 and 63/1000 = 5 + 63/1000 = 5 + 0.063 = 5.063

50. 6.700 = 6700/1000 = 67/10

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Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit

GaryK [48]

Answer: x = 2921, y = 579

Step-by-Step Explanation:

I am assuming that we just have to Solve for ‘x’ and ‘y’.

‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles

=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)

Adding Eq. 1 and Eq. 2, we get :-

2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921

Therefore, x = 2921

Substitute value of ‘x’ in Eq. 1 :-

x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579

Therefore, y = 579

Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579

6 0

1 year ago

D/5 = 4 please explain I do not get this. Thank you

MAXImum [283]

<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>

8 0

3 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒

$P(E)=\frac{4}{36}=\frac{1}{9}$ ⇒

$P(E)=\frac{1}{9}$

Finally we are going to define the event $F$ ⇒

$F$ : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

$F$ = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = $P(A,B)$

We define the conditional probability as

$P(A|B)=\frac{P(A,B)}{P(B)}$ with $P(B)>0$

We need to find $P(F|E)$ therefore we can apply the conditional probability equation :

$P(F|E)=\frac{P(F,E)}{P(E)}$ (I)

We calculate $P(E)=\frac{1}{9}$ at the beginning of the question. We only need $P(F,E)$ .

Looking at the sets $E$ and $F$ we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

$P(F,E)=\frac{1}{36}$

Replacing both probabilities calculated in (I) :

$P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25$

We find out that $P(F|E)=\frac{1}{4}=0.25$

6 0

3 years ago

The price of a European tour includes stopovers at five cities to be selected from 15 cities. In how many ways can a traveler pl

xeze [42]

Answer:

The traveler can plan such a tour in 3003 ways.

Step-by-step explanation:

The order that the cities are chosen is not important, since it is chosen by the company and not by the traveler. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.