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kondor19780726 [428]
3 years ago
15

P = 175 + t 2 What’s the answer

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

please write. question properly

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in a survey of 7000 women 4431 say they change their nail polish once a week.Construct a 95% confidence interval for the populat
andreyandreev [35.5K]

Answer:

The 95% confidence interval would be given (0.622;0.644).

We are confident (95%) that the true proportion of people that said that they change their nail polish once a week  is between 0.622 and 0.644

Step-by-step explanation:

Data given and notation  

n=7000 represent the random sample taken    

X=4431 represent the people that said that they change their nail polish once a week

\hat p=\frac{4431}{7000}=0.633 estimated proportion of people that said that they change their nail polish once a week

\alpha=0.05 represent the significance level

Confidence =0.95 or 95%

p= population proportion of people that said that they change their nail polish once a week

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.633 - 1.96 \sqrt{\frac{0.633(1-0.633)}{7000}}=0.622

0.633 + 1.96 \sqrt{\frac{0.633(1-0.633)}{7000}}=0.644

And the 95% confidence interval would be given (0.622;0.644).

We are confident (95%) that the true proportion of people that said that they change their nail polish once a week  is between 0.622 and 0.644

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Kerry scored a total of 205 points last season by making
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Answer:

a

Step-by-step explanation:

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You must first attach the problems with your question.
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Write an algebraic expression that illustrates the additive identity.
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Answer:

See if this helps

Step-by-step explanation:

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Match the polynomial expression on the left with the simplified version on the right.
Vitek1552 [10]

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

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