Answer:
15 units
Step-by-step explanation:
K(8, 6) and J(-4, -3)
Distance between 2 points
Thus using the formula above,
distance between points J and K
![= \sqrt{ {[8- (-4)]}^{2} + {[6- (-3)]}^{2} } \\ = \sqrt{ {12}^{2} + {9}^{2} } \\ = \sqrt{225} \\ = 15 \: units](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B8-%20%28-4%29%5D%7D%5E%7B2%7D%20%20%2B%20%20%7B%5B6-%20%28-3%29%5D%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B12%7D%5E%7B2%7D%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B225%7D%20%20%5C%5C%20%20%3D%2015%20%5C%3A%20units)
Answer:
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Step-by-step explanation:
- 11 students
- 26 students
- that 2 small divisions =1 unit =1 student
A. ratio of areas = 2^2 /5^2 = 4/25
B 14^2 : 1 = 196:1
C. ratio of perimeters would be sqrt81 = 9 times
