3 years ago

Can anyone explain how to differentiate this ? (2x^2+3)sin5x

1 answer:

7 0

Hello,

(u*v)'=u'v+uv'
u=2x²+3 ==> u'=4x
v=sin 5x ==>v'=cos 5x *5

((2x²+3 sin (5x))'=4x* sin (5x) +(2x²+3)*cos (5x) * 5

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