Question

Simplify. Express the answers using positive exponents:

Answer 1

Answer:

$\frac{-1}{2}ab^{12}$

$\frac{w^{10}}{3y^4}$

Step-by-step explanation:

Given the expression;

$\frac{-2a^2b^4}{4ab^{-8}}\\= \frac{-2}{4}*a^{2-1}b^{4-(-8)}\\= \frac{-1}{2}ab^{12}$

Similarly for the expression;

$\frac{-5w^4y^{-2}}{-15w^{-6}y^2}\\= \frac{-5}{-15}*w^{4-(-6)}y^{-2-2}\\= \frac{1}{3}w^{10}y^{-4} \\= \frac{w^{10}}{3y^4}$