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alexandr402 [8]
3 years ago
11

Find the 10th term of geometric sequence 3,15,75,375

Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:


Step-by-step explanation:

In a geometric sequence, the next term is a constant times the previous term. This constant is determined by dividing the second term by the first, here giving 5. The remaining terms are checked to see that each is 5 times the previous. 75 is 15×5, 375 is 75×5.


Alternately, the nth term is first term times k^(n-1).

Here, that's 3×5^(10-1), 3×5^9=5859375

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A grocery store has small bags of apples for $5 and large bags of apples for $8. If you buy 6 bags and spend $45, how many of ea
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Based on the given problem above, here is the given solution.
Given that small bags = $5
                 large bags = $8
                 6 bags = $45
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The answer based on the given values above is 5 LARGE BAGS and 1 SMALL BAG.
Since per large bag is $8. $8 x 5 = $40
And per small bag is $5 x 1 = $5
So this gives you a total of $45
hope this helps!
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Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
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