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3 years ago

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in the town zoo 3/28 of the animals are birds . of the birds, 4/15 are birds of prey . what fraction of.the animal at zoo are bi

rds of prey

1 answer:

salantis [7]3 years ago

3 0

The Free Application for Federal Student Aid (FAFSA) is a form that can be prepared annually by current and prospective college students (undergraduate and graduate) in the United States to determine their eligibility for student financial aid.

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A pizza has a diameter of 14 inches what is the approximate circumference

Savatey [412]

To find the circumference of a circle you can use either of these equations
3.14 X Diameter or 2 X 3.14 X Radius. But in this case we will use the first one. So 3.14 X 14 = 47.6 so the circumference of this circle would be 47.6 inches.
I hope this helps :)

7 0

3 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

Read 2 more answers

Find the distance between the pair of points and then round your answer to the nearest tenth.

Travka [436]

Answer:

$d = 9.4 units$ (nearest tenth)

Step-by-step explanation:

Given the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ , distance between (-4, 5) and (4, 0) is calculated as follows:

Let $(-4, 5) = (x_1, y_1)$

$(4, 0) = (x_2, y_2)$

$d = \sqrt{(4 - (-4))^2 + (0 - 5)^2}$

$d = \sqrt{(8)^2 + (- 5)^2}$

$d = \sqrt{64 + 25}$

$d = \sqrt{89}$

$d = 9.4 units$ (nearest tenth)

3 0

3 years ago

Identify the domain of the exponential function shown in the following graph:

Advocard [28]

All real numbers is the correct answer.

4 0

4 years ago

Read 2 more answers

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,

DochEvi [55]

Answer:

a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers