Answer:
umm sorry i can't I'm still finding hacker so please like and star please
Answer:
(a) -7 , - 9 , - 11
(b) Arithmetic sequence
(c) There is a common difference of -2
(d) -53
Step-by-step explanation:
(a) To find the next three terms , we must firs check if it is arithmetic sequence or a geometric sequence . For it to be an arithmetic sequence , there must be a common difference :
check :
-3 - (-1) = -5 - (-3) = -7 - (-5) = -2
This means that there is a common difference of -2 , which means it is an arithmetic sequence.
The next 3 terms we are to find are: 5th term , 6th term and 7th term.
= a + 4d
= - 1 + 4 ( -2 )
= -1 - 8
= - 9
6th term = a +5d
= -1 + 5(-2)
= -1 - 10
= - 11
= a + 6d
= -1 + 6 (-2)
= -1 - 12
= -13
Therefore : the next 3 terms are : -9 , -11 , - 13
(b) it is an arithmetic sequence because there is a common difference which is -2
(c) Because of the existence of common difference
(d) 
= a + 26d
= -1 + 26 ( -2 )
= -1 - 52
= - 53
Answer:
1.0
Step-by-step explanation:
You are rounding to the nearest tenth, so you should have only 2 places remaining (0.0). So, you look to the 7 to change the 9. 7 is bigger than 5, so you round 9 up. Since 9 plus 1 equals 10, the final answer is 1.0.
Hope this helps! :)
The is the correct answer x=80
Answer:
- 3 (die)
- 4 (slips)
- 6 (spinner)
- 5 (ace)
Step-by-step explanation:
Josie rolls a six-sided die 18 times. What is the estimated number of times she rolls a two? 3 = (1/6)(18)
Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number 10 appear? 4 = (1/10)(40)
A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white. If the spinner is spun 30 times, how many times should it land on a red space? 6 = (2/10)(30)
A card is picked from a standard deck of playing cards 65 times and replaced each time. About how many times would the card drawn be an ace? 5 = (4/52)(65)
_____
The probability of a given event is the number of ways it can occur divided by the number of possibilities. For example, a 2 is one of 6 numbers on a die, so we expect its probability of showing up to be 1/6. The expected number of times it will show up in 18 rolls of the die is (1/6)(18) = 3.
