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BartSMP [9]
3 years ago
8

Which graph shows the solutions to x^2+3x-1 ≥ 0

Mathematics
2 answers:
spayn [35]3 years ago
6 0

Answer:

if i'm not mistaken the answer is B

Finger [1]3 years ago
6 0

Answer:

Ans for the solution is B

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Rufina [12.5K]
100 inches times 12 1 minute 1 foot
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which statement best explains why the sum of the areas of the two white squares in figure 2 is the same as the area of why squar
Stella [2.4K]

Answer:

"In each figure the total area is equal and the area of the 4 triangles is equal, so the remaining white area in each figure must also be equal."

Step-by-step explanation:

Both figures make up congruent squares, and they are made up of 4 congruent triangles, so the white area in between must be equal between the two figures

3 0
3 years ago
Round48.073 to the nearest hundredth
Hunter-Best [27]

Answer:

48.07 (brainliest answer?)

Step-by-step explanation:

'7' is the hundredth figure

3 is not 5 or over so it stays the same

5 0
3 years ago
Read 2 more answers
Si el recíproco del m% de p se divide por el recíproco del m% de q resulta: A) pq/100 B)pq C)1/pq D)p/q E)q/p
Aleksandr [31]

Answer:

E) q / p

Step-by-step explanation:

Spanish

m% de p = pf / 100

m% de q = mq / 100

El recíproco se obtiene haciendo que el numerador sea el denominador y el denominador el numerador.

El recíproco de m% de p = 100 / mp

El recíproco de m% de q = 100 / mq

Divisor

100 / mp / 100 / mq

= 100 / mp * mq / 100

= mq / mp

= q / p

English

If the reciprocal of m% of p is divided by the reciprocal of m% of q, the result is: A) pq / 100 B) pq C) 1 / pq D) p / q E) q / p

m% of p= mp/100

m% of q= mq/100

The reciprocal is obtained by making the numerator the denominator and the denominator the numerator

The reciprocal of m% of p= 100/mp

The reciprocal of m% of q= 100/mq

Dividing

100/mp/ 100/mq

=100/mp* mq/100

= mq/mp

= q/p

8 0
3 years ago
If anyone is good at geometry, pls help :)
Vadim26 [7]

Answer:

<u>Segment</u><u> </u><u>Addition</u><u> </u><u>Postulate</u>

<u>BC</u> + <u>AB</u> = <u>CA</u> [BOTH answers]

<u>Application</u><u> </u><u>with</u><u> </u><u>Midpoint</u>

<u>BC</u> = <u>BA</u>

1a) 9 = <em>x</em>

1b) 34 = FA

1c) 3 = AT

2a) 11 = <em>x</em>

2b) 37 = BO

2c) 37 = OX

2d) 74 = BX

Step-by-step explanation:

The Segment Addition Postulate is basically saying that if

___

point <em>B</em><em> </em>is in between <em>AC</em><em> </em>[NOT<em> </em>the <em>midpoint</em><em> </em>(or halfway)],<em> </em>then both segments [AB and BC] would make up the whole thing [CA, or vice versa]. They are just explaining it in two unique ways you can word it.

The Midpoint Application tells you that if point <em>B</em><em> </em>is a

___

<em>midpoint</em><em>,</em><em> </em>meaning <em>B</em> is halfway in between <em>AC</em><em>,</em><em> </em>then both segments [AB and BC] are congruent to each other.

1a) 37 = [2<em>x</em> - 15] + [3<em>x</em> + 7]

37 = 5<em>x</em> - 8

+ 8 + 8

____________

45 = 5<em>x</em>

___ ___

5 5

9 = <em>x</em>

1b) Solving for FA

3(9) + 7 = 27 + 7 = 34

1c) Solving for AT

2(9) - 15 = 18 - 15 = 3

This obviously had to be the answer because 3 + 34 = 37.

2a) 2<em>x</em> +15 = 4<em>x</em> - 7

- 4<em>x</em> - 4<em>x</em>

_________________

-2<em>x</em> + 15 = -7

- 15 -15

_____________

-2<em>x</em> = -22

<em>x</em><em> </em>= 11

2b) Solving for BO

4(11) - 7 = 44 - 7 = 37

2c) Solving for OX

2(11) + 15 = 22 + 15 = 37

2d) Solving for BX

2 \times 37 = 74

I am joyous to assist you anytime.

4 0
4 years ago
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