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Murrr4er [49]
2 years ago
13

Why does multiplying the input of a linear function change

Mathematics
1 answer:
sergiy2304 [10]2 years ago
8 0

Answer:

Step-by-step explanation:

If we have a linear function and we multiply the input of the function, we aren't really <em>changing</em> the values of the function, we're changing the rate at which those values are reached.

E.g. if you look at the attached picture, we have f(x) = 2x and f_2(x) = 4x, which is just f(2x). The value when the red line is x = 1 is half that of the value of the blue line when x = 1.

The values of the f(2x) line are reaching the values of f(x) twice as fast, meaning it has a slope of twice as much. However, it still grows through the same intercept.

If you're interested in the calculus behind this, look up the chain rule of derivatives.

However, when you start changing the output of the function, you're changing the entire equation. It's not the same line anymore.

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22 8(11 + 2r) = 126r + 3
natulia [17]

8(11 + 2r) = 126r + 3​

first open the parenthesis

88 + 16r = 126r + 3

88 - 3 = 126r - 16 r

85 = 110r

divide both-side of the equation by 110

85/110 = r

r= 17/22

7 0
1 year ago
Ten times a number a added to three times a second number b divided by a third number c.​
pentagon [3]

Answer:

10a+3b÷c/3

Step-by-step explanation:

let the first number be a

second be b

third be c

10×a +3×b ÷c÷3

10a+3b÷c/3

=10a+3b÷c/3

5 0
3 years ago
Giving brainliest!! *easy*
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Answer:

60.458

Step-by-step explanation:

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2 years ago
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Candace said I'm thinking of a fraction. If I divide it by 1/2,I get 3/11.what fraction was Candace thinking of??
Pavlova-9 [17]
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6 0
3 years ago
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Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
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