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3 years ago

9

As long as x is not zero, x to the power of 0 is defined to be equal to 1. Using this definition, 5 to the power of 0=? , ( 6 to

the power of 4) to the power of 0=? , and -5x to the power of 0=?

1 answer:

Volgvan3 years ago

3 0

If you ever times a number by 0 then the answer will be 0 no matter what

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H/6-1=-3. What is h?

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Someone help me with this geometry homework !!!!!! 10 points!

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Answer: 3a = (0, 1) 3b = (2, 1) 3c = (2.5, 1) 3d = (1.6, 1)

4a = (2, 3.5) 4b = (2, 3) 4c = (2, 5.375)

<u>Step-by-step explanation:</u>

The length of AB is 6 and is horizontal (affects the x-coordinate)

$3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)$

$3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)$

***********************************************************************************

The length of AB is 5 and is vertical (affects the y-coordinate)

$4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)$

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3 years ago

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Marta_Voda [28]

Answer:

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Step-by-step explanation:

f(x) =x^2 - 6x + 21

f(xl =0

Answer:

substitute 0 for x

f(0) = 0^2 - 6(0) + 21

0. = 0 - 0 + 21

0. = 21

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