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Salsk061 [2.6K]
3 years ago
12

Enter numbers to write 0.000328

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

3.28 x 10^-4


Step-by-step explanation:

0.000328 = 3.28 x 10^-4

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Make a table for each function rule. Then graph each equation using the points you created.
aleksandrvk [35]

Answer:

1.f(x)=2x-5

i will take the set {-2,-1,0,1,2}

f(-2)=2(-2)-5

=-4-5

=-9

f(-1)=2(-1)-5

=-2-5

=-7

f(0)=2(0)-5

=-5

f(1)=2(1)-5

=-3

f(2)=2(2)-5

=-1

so the coordinates of the function is {-9,-7,-5,-3,-1}

2.f(x)=-3x+6

i will the take the set {-2,-1,0,1,2} too

f(-2)=-3(-2)+6=6+6=12

f(-1)=-3(-1)+6=3+6=9

f(0)=-3(0)+6=6

f(1)=-3(1)+6=-3+6=3

f(2)=-3(2)+6=-6+6=0

{12,9,6,3,0}

3.f(x)=2/3.x+4

{-2,-1,0,1,2}

f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3

f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3

f(0)=2/3(0)+4=4

f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3

f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3

{8/3,10/3,4,14/3,16/3}

you're can graph those coordinates

actually you can take other coordinates...

CMIIW

,

7 0
2 years ago
X - 3y = 6 and x - 3y = 9
Kruka [31]
The answer is that there are no solutions to the equations. They are parallel to each other and never cross. They can also be called inconsistent
6 0
3 years ago
Life rating in Greece. Greece has faced a severe economic crisis since the end of 2009. A Gallup poll surveyed 1,000 randomly sa
elena-s [515]

Answer:

a

        The population parameter of interest is the true proportion of Greek who are suffering

    While the point estimate of this parameter is  proportion of those that would rate their lives poorly enough to be considered "suffering". which is 25%  

b

   The condition  is met

c

   The  95% confidence interval is   0.223 <  p  < 0.277

d

      If the confidence level is increased which will in turn reduce the level of significance but increase the critical value(Z_{\frac{\alpha }{2} }) and this will increase the margin of error( deduced from  the formula for margin of error i.e  E \ \alpha \  Z_{\frac{\alpha }{2} } ) which will make the confidence interval wider

e

  Looking at the formula for margin of error if the we see that if the  sample size is increased the margin of error will reduce making the  confidence level narrower

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  1000

     The  population proportion is  \r p  = 0.25

     

Considering question a

   The population parameter of interest is the true proportion of Greek who are suffering

    While the point estimate of this parameter is  proportion of those that would rate their lives poorly enough to be considered "suffering". which is 25%  

Considering question b

The condition for constructing a confidence interval is

        n *  \r p >  5\  and  \   n(1 - \r p ) >5

So  

        1000 *  0.25 > 5 \  and \  1000 * (1-0.25 ) > 5

         250  > 5 \  and \  750> 5

Hence the condition  is met

Considering question c

    Given that the confidence level is  95%  then  the level of significance is mathematically evaluated as

          \alpha  =  100 - 95    

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table, the value is  

              Z_{\frac{\alpha }{2} }  =  1.96        

Generally the margin of error is mathematically represented as

         E =  Z_\frac{ \alpha }{2}  *  \sqrt{ \frac{\r p (1 - \r p ) }{n} }

substituting values

         E =  1.96  *  \sqrt{ \frac{ 0.25 (1 - 0.25 ) }{ 1000} }

         E =  0.027

The  95% confidence interval is mathematically represented as

            \r p  - E  <  p  <  \r p  + E

substituting values  

           0.25 -  0.027  <  p  < 0.25 + 0.027

substituting values

           0.223 <  p  < 0.277

considering d

  If the confidence level is increased which will in turn reduce the level of significance but increase the critical value(Z_{\frac{\alpha }{2} }) and this will increase the margin of error( deduced from  the formula for margin of error i.e  E \ \alpha \  Z_{\frac{\alpha }{2} } ) which will make the confidence interval wider

considering e

     Looking at the formula for margin of error if the we see that if the  sample size is increased the margin of error will reduce making the  confidence level narrower

   

5 0
3 years ago
Jacob distributed a survey to his fellow students asking them how many hours they spent on the Internet in the past day. He also
Anna35 [415]

The linear equation B. y = -x +7.5 best describes the given model. The mood rating for a student that spent 5.5 hours online would be 2.

Step-by-step explanation:

Step 1; We plot the points that fall on the line and that lie on an exact x or y coordinate. The following 4 points are plotted (0.5, 7), (2, 5.5), (2.5, 5) and (3.5, 4). We substitute the values of x in the given equations to see which best describes the model.

Step 2; When y = x + 7.5, we get the coordinates as (0.5, 8), (2, 9.5), (2.5, 10) and (3.5, 11).

When y = -x + 7.5, the coordinates are (0.5, 7), (2, 5.5), (2.5, 5) and (3.5, 4).

When y = \frac{-1x}{2} + 7.5, the coordinates are (0.5, 7.25), (2, 6.5), (2.5, 6.25) and        (3.5, 5.75).

So equation 2 has the closest values to the actaul graph.

Step 3; By substituting x = 5.5, y = -(5.5) + 7.5 = 7.5 - 5.5 = 2.

8 0
4 years ago
Find the length of side x in simplest radical form with a rational denominator.
Klio2033 [76]

Answer:

x = \frac{\sqrt{6}}{2}

Step-by-step explanation:

Reference angle = 45°

Opposite side = x

Hypotenuse = √3

Use the following trigonometric ratios formula to find x:

sin(\theta) = \frac{opp}{hyp}

Plug in the values

sin(45) = \frac{x}{\sqrt{3}}

Multiply both sides by √3

\sqrt{3}*sin(45) = x

\sqrt{3}*\frac{\sqrt{2}}{2} = x

\frac{\sqrt{3*2}}{2} = x

\frac{\sqrt{6}}{2} = x

6 0
3 years ago
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