1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Damm [24]
3 years ago
7

Someone, please help me fill this out

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

Here is the summary:

  • y = 13x+5 satisfies the points (0, 5) and (-2, -21)
  • y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
  • y = x-10 satisfies the points (8, -2)

Step-by-step explanation:

Given the equation

  • y = 13x+5
  • y = -3x
  • y = x-10

The points which satisfy the equation y=13x+5

y = 13x+5

Checking the point (0, 5)

5 = 13(0)+5

5 = 0 + 5

5 = 5

TRUE

Checking the point (-2, -21)

-21 = 13(-2)+5

-21 = -26 + 5

-21 = -21

TRUE

The points which satisfy the equation y=-3x

y = -3x

Checking the point (0, 0)

0 = -3(0)

0 = 0

TRUE

Checking the point (-5, -15)

y = -3x

-15 = -3(-5)

-15 = -15

TRUE

Checking the point (-3, 9)

y = -3x

9 = -3(-3)

9 = 9

TRUE

The points which satisfy the equation y=x-10

y = x-10

Checking (8, -2)

-2 = 8 - 10

-2 = -2

TRUE

Therefore, from the above calculations we conclude the summary:

Here is the summary:

  • y = 13x+5 satisfies the points (0, 5) and (-2, -21)
  • y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
  • y = x-10 satisfies the points (8, -2)
You might be interested in
If the hypotenuse of a right triangle has length 9 feet and one of the other sides has length 2 feet, what is the length of the
alex41 [277]
  • Hypotenuse=H=9ft
  • Base=B=2ft

Apply Pythagorean theorem

  • P²=H²-B²
  • P²=9²-2²
  • P²=81-4
  • P²=77
  • P=√77

Option D

4 0
2 years ago
Read 2 more answers
Which of these expressions is equivalent to 2f x 2f x 2f x 2f x 2f x 2f
Tcecarenko [31]

Answer:

Option choice A

Step-by-step explanation:

If you count how many 2f's there are, there are 6

5 0
4 years ago
Read 2 more answers
The first side of a triangle is 2 inches shorter than the second side. The third side is 5 inches longer than the second side. I
fomenos
Let the length of second side be x" ,

So,
Length of first side = 2" shorter than second = ( x - 2 )"
Length of third side = 5" longer than second = ( x + 5 )"




=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=




\text{Perimeter = sum of all sides  }



Given, perimeter = 33"




= > first side + second side + third side = 33"


= > ( x - 2 ) + x + ( x + 5 ) = 33

= > x - 2 + x + x + 5 = 33

= > 3x + 3 = 33

= > 3x = 30


= \:   >  x = \frac{30}{3}


= > x = 10








Hence, length of each side is

First side = ( x - 2 )" = ( 10 - 2 )" = 8 inches

Second side = x " = 10 inches

Third side = ( x + 5 )" = ( 10 + 5 )" = 15 inches
8 0
3 years ago
Find the value of x. Just type in the number​
Irina18 [472]

Answer:66

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
factor out the gcf of the expression. express you answer as the product of the gcf and remaining factor
ser-zykov [4K]

son varias respuestas mijo

3 0
3 years ago
Other questions:
  • 5x 2(x - 3) = -2(x - 1)
    7·1 answer
  • Help Find 4% of 3.5km
    13·1 answer
  • The vertices of a quadrilateral are A(-1, 6), B(-2, 4), C(2, 2), and D(3, 4). Write a paragraph proof to determine whether quadr
    14·2 answers
  • A company is making building blocks what is the length of each side of the block?
    13·2 answers
  • Write a rule for multiplying three negative decimals
    7·2 answers
  • Which of the following are measurements of the sides of a right triangle?
    7·2 answers
  • Quadrilateral PQRS is an isosceles trapezoid in which m∠P = m∠S. Which of the following statements must be true?
    14·1 answer
  • Helppp Meeee Plzzzzz
    14·1 answer
  • What is the image of (0,7) after a reflection over the x-axis
    5·1 answer
  • Combine k/4 and 5k<br><br><br> pls pls pls pls
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!