Answer:
g-1(x)=SQRT{(x-4)/2} + 4
Step-by-step explanation:
I assume that the 2 is the exponent so ^ represents exponent
We know your function is g(x)=2(x-3)^2+4
For inverse functions we swap x and y values, note g(x) is like the y value
Isolate for y
y=2(x-3)^2+4
x=2(y-3)^2+4
(x-4)/2 = (y-3)^2
SQRT{(x-4)/2} + 4 = y
Therefore g-1(x)=SQRT{(x-4)/2} + 4
You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
We know that 3 point can creating always a plane
so from this result the right choice is A. so is true
