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AlexFokin [52]
2 years ago
6

David goes to college by bus.

Mathematics
1 answer:
oee [108]2 years ago
8 0

Answer:

The answer is 30 times a year

Step-by-step explanation:

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What is 10 squared plus b squared equals 22 squared
klio [65]
I'm pretty sure you are asking for the value of b. Let's actually write it and then solve it:
10^2 + b^2 = 22^2

Solving for b yields:
b = \sqrt{22^2-10^2} = \sqrt{484-100} = \sqrt{384} = 19.59

So, b = 19.59. If you want the answer in simplified radical form, we can also do that:
\sqrt{384} =  \sqrt{16*24} = 4 \sqrt{24} = 4 \sqrt{4*6} = 8 \sqrt{6}

So, b = 8√6 = 19.59
4 0
2 years ago
A rectangle has a length of 6 inches and a width of 3 inches.
lutik1710 [3]
C
6*3=18
6*8= 48 and 3*8=24
24*48= 1152
1152/18=64

5 0
3 years ago
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Which statement about these rectangles is true? 4(1.5) 4 2(1.5) Image 2(1.5) Pre-Image 2 4(1.5)​
Anna007 [38]

Answer:

it is a because I said it is a

4 0
3 years ago
Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
Rainbow [258]

Answer:

(A) 0.006593 or 0.6593%

(B) 0.01538 or 1.538%

Step-by-step explanation:

The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

n=\frac{15!}{(15-3)!3!}=\frac{15*14*13}{3*2*1}\\n=455\ ways\\

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

P(N=1) = \frac{3}{455}=0.006593 =0.6593\%

(B) There are three possibilities  for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

P(N>0) =P(N=1)+P(N=2)+P(N=3) \\P(N>0) = \frac{3}{455}+ \frac{3}{455}+ \frac{1}{455}\\P(N>0) =0.01538 =1.538\%

5 0
3 years ago
Please help! refer to picture !<br><br>edit: nvm
g100num [7]
Wat??????????????????
7 0
2 years ago
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