X+8y=18
-5x+3y=-4
Multiply the first equation by 5
Add the two equations together
5x+40y=90
-5x+3y=-4
43y=86
Y=2
Plug y into one equation to find x
X+16=18
X=2
Step-by-step explanation:
You have miscopied the second equation as it contains a third variable B when there isn't a B in the answers.
Please correct it for assistance
They are already both positive numbers, so the absolute value of 2 is 2, and the absolute value of 1/3 is 1/3.
Part A
(3x)^2*x^4
(3x)*(3x)*x^4 .... expand out (3x)^2
(3*3)*(x*x*x^4)
9x^6
Answer: 9x^6
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Part B
It appears that Tonya forgot to square the 3 term and had this as her steps
(3x)^2*x^4
3x^2*x^4
3x^(2*4)
3x^8
Which is incorrect as the answer in part A indicates.
Not only is the '3' part wrong, but also the exponent of 8. Instead of multiplying the exponents, she should have added them.
The rule is a^b*a^c = a^(b+c). In this case, a = x, b = 2 and c = 4.
So x^2*x^4 = x^(2+4) = x^6
Answer:
31
/40
Step-by-step explanation:
Find the least common denominator or LCM of the two denominators:
LCM of 5 and 8 is 40
For the 1st fraction, since 5 × 8 = 40,
