Answer:
1:49
2:62
Step-by-step explanation:
it mightbe wrong idk
Answer:
l = 9p/4 , l = 9p/4
Step-by-step explanation:
Given:
Perimeter = 9p
Find:
Length and width
Computation:
Assume;
Length = l
Perimeter = 2(l+b)
9p/2 = l+w
w = 9p/2 - l
Area = lb
Area = l(9p/2 - l)
Using differentiation
l = 9p/4
w = 9p/2 - l
w = 9p/2 - 9p/4
w = 9p/4
Answer:
Step-by-step explanation:
6< 3x + 9
-3x < 9-6
-3x < 3 .( -1 )
3x > 3
x > 3/3
x > 3
3x + 9 ≤ 18
3x ≤ 18-9
3x ≤ 9
x ≤ 9/3
x ≤ 3
S = {XeIR/ 3 > x ≤ 3 }
Not sure if the solution looks like this
Answer:
304(pi) g
Step-by-step explanation:
First we find the volume of the hollow ball. Then we find the mass using the volume and density.
Let R = exterior radius = 3 cm
Let r = interior radius = 2 cm
volume = exterior volume - interior volume
volume = (4/3)(pi)R^3 - (4/3)(pi)r^3
volume = (4/3)(pi)(R^3 - r^3)
volume = (4/3)(pi)(3^3 - 2^3) cm^3
volume = (4/3)(pi)(27 - 8) cm^3
volume = (76/3)pi cm^3
Now we use the density and the volume to find the mass.
density = mass/volume
mass = density * volume
mass = 12 g/cm^3 * (76/3)pi cm^3
mass = 304(pi) g
Answer: 304(pi) g
Answer:
y=kx
Step-by-step explanation:
