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3 years ago

Question 6 of 37 write the equation in slope-intercept form. what are the slope and y-intercept? –12x + 11y = –8

1 answer:

8 0

Solve for y. Do that by adding the opposite of the x-term, then dividing by the coefficient of y.
11y = 12x - 8
y = (12/11)x - 8/11

The slope is 12/11.
The y-intercept is -8/11.

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Find x 27 degrees and 32 degrees will give brainlist

telo118 [61]

Answer:

x = 121°

Step-by-step explanation:

If you add up all the angles of a triangle, you get 180°.

So you must add up all the angles.

$27+32+x=180\\\\59+x=180$

Next you subtract 59 on both sides.

$x=121$

x should be 121°.

If you would like to check your answer, you can add up 27, 32, and 121. If it all equals to 180, then your answer is correct.

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2 years ago

Find u -2v given u = (-2, 5) and v = 6i -4j

Arisa [49]

Answer:

A. U - 2v = -14i +13j

Step-by-step explanation:

If u = (-2, 5) and v = 6i -4j

Then 2v = 2*(6i-4j) = 12i-8j

u-2v = -2i +5j - (6i -4j)

Distribute the minus sign

-2i +5j -6i+4j

-2i +5j

-12i + 8j

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-14i +13j

6 0

3 years ago

What is the volume of a prism which has a base of 5 m by 3m, and a height of 4m?

wlad13 [49]

If you multiplied the base times the width times the height you would get a final answer of 60m.

4 0

2 years ago

Evaluate the function found in the previous step at X =-3

babunello [35]

$x-5y=-4x-2y$

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

$-3-5y=-4(-3)-2y$

Multiply -4 and -3 in the function above.

$-3-5y=12-2y$

Add 3 on both sides of the equation.

$-3-5y+3=12-2y+3$ $-5y=15-2y$

Add 2y on both sides of the equation.

$-5y+2y=15-2y+2y$ $-3y=15$

Divide both sides of the equation by -3.

$\frac{-3y}{-3}=\frac{15}{-3}$ $y=-5$

Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

7 0

1 year ago

Which function is a quadratic function? F(x) =2x^2, g(x) =5x^3,k(x)=-x,b(x)=-9x^4

Katen [24]

Answer:

F(x)=2x^2

Step-by-step explanation:

Basically, a quadratic function has x^2 in it (standard form ax^2+bx+c with non-zero a). The others have x^3, -x, x^4, etc., which clearly are NOT x^2.

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2 years ago