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Dvinal [7]
3 years ago
9

Question 6 of 37 write the equation in slope-intercept form. what are the slope and y-intercept? –12x + 11y = –8

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0
Solve for y. Do that by adding the opposite of the x-term, then dividing by the coefficient of y.
   11y = 12x - 8
   y = (12/11)x - 8/11

The slope is 12/11.
The y-intercept is -8/11.
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Juan is drawing the two-dimensional net of a rectangular solid, but he made a mistake. What error did Juan make, and how can he
dsp73

Answer:

D.The prism is missing a sixth face, which should be colored white.

Step-by-step explanation:

The shape does not have 2 bases in the picture showed. Therefore, it needs another white square.

Hope it helps! have a good day! :)))))

7 0
3 years ago
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Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
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Clint invested $6000 in a savings account for 12.5 years. At the end of 12.5 years, his savings account had $8250 in it. If $600
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The balance B at the end of time t is given by
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Clint earned 3% annual simple interest on his savings.
7 0
3 years ago
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Given quadrilateral TUVX ~ quadrilateral MNOP and VX = 5, XT = 10, and OP = 7, what is PM?
Likurg_2 [28]
\dfrac{\overline{PM}}{\overline{OP}}=\dfrac{\overline{XT}}{\overline{VX}}\\\\
\dfrac{\overline{PM}}{7}=\dfrac{10}{5}\\\\
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\overline{PM}=14

8 0
3 years ago
Ill give 5 starts to who ever helps me.
Ivahew [28]
No it doesn't be i thought that it you would have to find a domain but i couldn't
5 0
3 years ago
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