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Dima020 [189]
2 years ago
9

Find the equation (in slope-intercept form) of the line passing through the points with the given coordinates.

Mathematics
2 answers:
Dmitrij [34]2 years ago
3 0

Answer:

<h2>y = -2x + 1</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (1, -1) and (2, -3).

Substitute:

m=\dfrac{-3-(-1)}{2-1}=\dfrac{-2}{1}=-2

Put it and the coordinates of the point (1, -1) to the equation of a line:

-1=-2(1)+b

-1=-2+b          <em>add 2 to both sides</em>

1=b\to b=1

Finally:

y=-2x+1

Pachacha [2.7K]2 years ago
3 0
is parallel to the -axis. If the coordinates of the points and are (, 2) and (8, 6), respectively, find the value of .

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