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sineoko [7]
2 years ago
6

Montel spends $0.75 every time he plays his favorite video game. If you have $10, write and resolve an inequality to calculate h

ow many video games you can play
Mathematics
1 answer:
Bumek [7]2 years ago
3 0

Answer:13.333333 repeating

Step-by-step explanation:money divided by how much the games cost

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Peter placed an order with an online nursery for 6 apple trees and 5 azaleas and the order came to $147. The next order for 3 ap
Setler79 [48]

Answer:

$243

Step-by-step explanation:

The first order you made :

6 apple

5 azaleas

And total cast was:

 $147

The secant order you order was:

3 apples

4 azaleas

And total cast was:

$96

The total cast of both orders is:

$243

5 0
2 years ago
Read 2 more answers
What’s the answer to this please? Thanks!
Serjik [45]

Answer:

70

  1. beacuse (2x-35)+75=180
  2. (2x-35)=105
  3. 2x=140
  4. x=70
3 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
Im to tierd to post this
Colt1911 [192]

Answer:

keep trying until you succeed :)

Step-by-step explanation:

7 0
2 years ago
Factor completely and then place the factors in the proper location on the grid.
Alika [10]
1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).

2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.

4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.

5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)

Hope this helped :) Have a great day 
8 0
3 years ago
Read 2 more answers
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