Which ordered pairs display y as a function of x? *

In mrs. wiggins class of 32 students, 3/8 of the student are taking French, and 1/2 of the students are taking Latin. If 6 stude

Vlad1618 [11]

The answer is 10 you see 6 people are in both of the classes so you have to subtract 6 from the 12 and 16 12+16-6=22
32-22=10

5 0

2 years ago

Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

7 0

2 years ago

here is the image of triangle ABC and its dilation using Center D and scale factor 2. Why is B'C' on the same line as its corres

GaryK [48]

Since only the lengths increase by scale factor, B'C' on the same line as its corresponding side segment BC .

What is the Dilation?

Math definition of dilation Resizing an object is accomplished through a change called dilation. The objects can be enlarged or shrunk via dilation. A shape identical to the source image is created by this transformation. The size of the form does, however, differ.

The following are the properties of dilation of the triangle:

1)measures of the angles will not change

2)The sides of the image of the triangle are multiplied by the scale factor 2.

So,

A'B'=2AB

B'C'=2BC

A'C'=2AC

Since only the lengths increase by scale factor, B'C' on the same line as its corresponding side segment BC .

To learn more about the Dilation from the given link

brainly.com/question/3457976

#SPJ1

5 0

10 months ago

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

katrin2010 [14]

2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
x = -(3 / 4) + sq root (-36) / 4
x = -(3 / 4) - sq root (-36) / 4

7 0

2 years ago

Yuet solved the equation 6 a minus 2 b = 12 for a. Her steps are shown below. 1. Subtract 2b: 6 a = 12 minus 12 b 2. Divide by 6

Ber [7]

Question:

Yuet solved the equation $6a - 2b = 12$ for a.