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Ratling [72]
3 years ago
14

Please help ???????????????????

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

Step-by-step explanation:

español?

no se yo no halo español :v

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Attached as photo. Please help
Effectus [21]

By Euler's method the <em>numerical approximate</em> solution of the <em>definite</em> integral is 4.189 648.

<h3>How to estimate a definite integral by numerical methods</h3>

In this problem we must make use of Euler's method to estimate the upper bound of a <em>definite</em> integral. Euler's method is a <em>multi-step</em> method, related to Runge-Kutta methods, used to estimate <em>integral</em> values numerically. By integral theorems of calculus we know that definite integrals are defined as follows:

∫ f(x) dx = F(b) - F(a)     (1)

The steps of Euler's method are summarized below:

  1. Define the function seen in the statement by the label f(x₀, y₀).
  2. Determine the different variables by the following formulas:

    xₙ₊₁ = xₙ + (n + 1) · Δx     (2)
    yₙ₊₁ = yₙ + Δx · f(xₙ, yₙ)     (3)
  3. Find the integral.

The table for x, f(xₙ, yₙ) and y is shown in the image attached below. By direct subtraction we find that the <em>numerical</em> approximation of the <em>definite</em> integral is:

y(4) ≈ 4.189 648 - 0

y(4) ≈ 4.189 648

By Euler's method the <em>numerical approximate</em> solution of the <em>definite</em> integral is 4.189 648.

To learn more on Euler's method: brainly.com/question/16807646

#SPJ1

7 0
2 years ago
Need help please thx you
erma4kov [3.2K]
$72.

20% of 60 is 12

$12 + $60 = $72
6 0
3 years ago
Write (-5+8i)+(-5-8i) as a complex number in standard form
gizmo_the_mogwai [7]
(-5+8i)+(-5-8i) =&#10;-5+8i-5-8i=-10
5 0
3 years ago
Write the equation of the following circle in general form and standard form. Show your work.
o-na [289]

Answer:

I’m coming back to this hold on a sec brotha and be patient

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to 2x^2+2x-4/2x^2-4x+2
lord [1]
You need to factor the numerator and denominator...

(2x^2+4x-2x-4)/(2x^2-2x-2x+2)

(2x(x+2)-2(x+2))/(2x(x-1)-2(x-1))

((2x-2)(x+2))/((2x-2)(x-1))  so the (2x-2)s cancel out leaving

(x+2)/(x-1)
4 0
3 years ago
Read 2 more answers
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