Answer:
Step-by-step explanation:
m∠1+∠2=180
2x+40+2y+40=180
2x+2y=180-80
2x+2y=100
x+y=50
x=50-y
m∠1=m∠3
2x+40=x+2y
2x-x=2y-40
x=2y-40
2y-40=50-y
2y+y=50+40
3y=90
y=30
x=50-y=50-30=20
m∠1=2x+40=2×20+40=80°
m∠2=2y+40=2×30+40=60+40=100°
m∠3=x+2y=20+2×30=80°
Answer:
1125&825
Step-by-step explanation:
Answer:
Smallest number would be 1^o
Step-by-step explanation:
Now with this one I can see the question now and the smallest* number of degrees to tilt it would be 1 degrees.
Have a good day. :)
Hope this helps!
<u>(brainliest would be appreciated)</u>
Answer:
(pi)4 or about 12.57 sq. units
Step-by-step explanation:
The base area of a cylinder is a circle.
Since we know that the radius is 2, we can use the equation A = (pi)r^2 to find the area.
So, using this formula, the area is (2)(2)(pi), about 12.57 sq. units (area is squared!)
Answer:
Step-by-step explanation:
The horizontal asymtote is when there are no solutions for x, so it is when y = -10.
This is because when y = -10, 0.8^x must be 0, but this is impossible. You can test this by trying 4^x/5^x. It will get super small, but never 0.
