Answer:
d = 8.602325
Rounded = 9
For:
(X1, Y1) = (1, 4)
(X2, Y2) = (6, -3)
The altitudes of equal length, BE and CF gives AB = AC, from which we have;
- ∆ABC is an isosceles triangle
<h3>How can the RHS rule be used to indicate an isosceles triangle?</h3>
From the given description, we have;
BE = CF
<CFB = <BEC = 90° All right angles are congruent
BC = BC by reflexive property of congruency
BC = The hypotenuse side of triangles ∆BFC and ∆CEB
Therefore;
∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.
Therefore;
BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Similarly, we have;
∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency
Which gives;
FA = AE by CPCTC
BF + FA = CE + AE, by substitution property of equality
BF + FA = AB
CE + AE = AC
Therefore;
Therefore;
- ∆ABC is an isosceles triangle
Learn more about rules of congruency here:
brainly.com/question/24261247
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60-12=4x
48=4x
x=12
Hope this helps.
The answer is: " 471 cm² " .
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The formula for the surface area, "S.A.", of a "cylinder":
S.A. = 2 π r² + 2 π r h ;
in which:
"S.A." = "surface area" of the cylinder; for which we wish to solve;
π = 3.14 (approximation we shall use) ;
r = radius = 5 cm (given; from figure);
h = height = 2 cm (given; from figure);
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To solve for the surface area, "S.A." . let us plug in our known values, and solve:
S.A. = 2 π r² + 2 π r h ;
S.A. = 2 * (3.14) * (5 cm)² + 2 * (3.14) * (5 cm) * 10 cm) ;
= 2 * (3.14) * (5²) * (cm²) + 2 * (3.14) * 5* 10 * cm² ;
= 2 * (3.14) * (25) * (cm²) + 2 * (3.14) * 5* 10 * cm² ;
= 157 cm² + 314 cm² ;
= 471 cm² .
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The answer is: " 471 cm² " .
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