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Taya2010 [7]
3 years ago
11

A principal of $4700 is invested at 8.25% interest compounded annually. How much will the investment be worth after 7 years?

Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

$7562.50

Step-by-step explanation:

4700 (1.0825)^7-1

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Solve for x.
Crank

The solutions to the given absolute value equation are:

x = −74 and x = 80

<h3>How to solve the given equation for x?</h3>

Here we want to solve the absolute value equation:

(1/7)*|x - 3| - 2 = 9

To solve this, we first need to isolate the absolute value part, so we get:

(1/7)*|x - 3| - 2 = 9

(1/7)*|x - 3| = 9 + 2

(1/7)*|x - 3| = 11

|x - 3| = 11*7

|x - 3| = 77

Now we can decompose the absolute value equation into two simpler ones, which are:

x - 3 = 77

x - 3 = -77

Solving those two equations we get:

x = 77 + 3 = 80

x = -77 + 3 = -74

Thus the solutions are:

x = -74 and x = 80, we conclude that the correct option is the last one.

If you want to learn more about absolute value equations:

brainly.com/question/5012769

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6 0
2 years ago
What is 3/5 divide 1/3
Alecsey [184]

Answer:

1 4/5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Elizabeth bought 6 packages of cat food and 3 packages of dog food. Each package of cat food contained 9 cans, and each package
frutty [35]
She bought 42 more cans of cat food becuase 6 packages with 9 cans is 6 times 9 and that is 54 -42 to equal 12 because 3 times 4 which is how much dog food she buys
7 0
3 years ago
Read 2 more answers
1. What are the roots of the equation?
Harrizon [31]
1) A. since, if you put the numbers into the equation (one at a time) the equation = 0 each time, which is true.
2) I think I've been taught to complete the square slightly differently
x^2 - 18x - 17 = 0
(x-9)^2 - 81 -17 = 0
(x-9)^2 - 98 = 0
I hope you can get something from that
3 0
3 years ago
Read 2 more answers
Use the definition of taylor series to find the taylor series (centered at
Alexxandr [17]
Cos(x) is infinitely differentiable, can be expanded using Taylor's series.
The series about c can be expressed as
f(x)=\sum_{n=0}^{\infty}\frac{f^{n}(c)}{n!}(x-c)^n
Substituting cos(x), c= π /4,we have
cos(x)=\sum_{n=0}^{\infty}\frac{f^{n}(\frac{\pi}{4})}{n!}(x-\frac{\pi}{4})^n
and since
f'(\frac{\pi}{4})=-sin(\frac{\pi}{4})=-\sqrt{2}/2
f"(\frac{\pi}{4})=-cos(\frac{\pi}{4})=-\sqrt{2}/2
f^{(iii)}(\frac{\pi}{4})=sin(\frac{\pi}{4})=\sqrt{2}/2
f^{(iv)}(\frac{\pi}{4})=cos(\frac{\pi}{4})=\sqrt{2}/2

we can simplify the expansion to 
cos(x)=\frac{\sqrt{2}}{2}(1-(x-\frac{\pi}{4})/1!-(x-\frac{\pi}{4})^2/2!+(x-\frac{\pi}{4})^3/3!+(x-\frac{\pi}{4})^4/4!-(x-\frac{\pi}{4})^5/5!-...)
Note that the sign pattern is  - - + + - - + + - - ..... following the sign pattern of the derivatives of cos(x).
5 0
3 years ago
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