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3 years ago

Really need help on this!!

Mathematics

1 answer:

marin [14]3 years ago

4 0

Answer:

Hey there!

There are 3+4+6+3, or 16 females.

3 of the females are seniors.

Thus, the percent is 3/16, or 19%

Let me know if this helps :)

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zheka24 [161]

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3 years ago

How many terms are in the following expression? 2x+4y+8-2

sashaice [31]

Answer:

Step-by-step explanation:

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2 years ago

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2 of a dozen eggs are cracked. What percent of the carton is NOT cracked using the percent proportion

levacccp [35]

If 2 of 12 eggs are cracked, then 10 are not cracked.

10/12=5/6=about 0.83

0.83 of total eggs not cracked is also equivalent to 83 percent as asked in the problem :)

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3 years ago

What is the best estimation of the equation 7/8 -6/11

Elena L [17]

Answer:

125/88

Step-by-step explanation:

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2 years ago

A local university wanted to understand what students prefer to eat during finals. They asked 1000 students, "Do you prefer chic

olga55 [171]

Answer:

$P(\text{Pizza}\ |\ \text{Female})=0.225$

Step-by-step explanation:

The two-way frequency table is attached below.

We have to calculate the probability of, a person chosen at random prefers pizza given that they are female, i.e $P(\text{Pizza}\ |\ \text{female})$

This is a conditional probability.

We know that,

$P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}$

So,

$P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}$

From the table,

$P(\text{Pizza}\ \cap\ \text{Female)}=\dfrac{119}{1000}$

$P({\text{Female}})=\dfrac{530}{1000}$

Putting the values,

$P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}=\dfrac{\frac{119}{1000}}{\frac{530}{1000}}=0.225$

8 0

3 years ago