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sertanlavr [38]
3 years ago
13

Can someone please help me I really need help please help me

Mathematics
1 answer:
just olya [345]3 years ago
7 0
Oh okay. I think that what this is asking, is that they just want you to find the slopes.

So first you have to put both equations into y=mx+b form

So first equation, x-2y+8=0, now we subtract 8 on both sides aswell as subtract x and were left with -2y=-x-8 now we have to divide by negative two on both sides which gives you y=1/2x+4.

Then we do the same to the second equation. 2x+y+1=0. Se switch some things around and get Y=-2x-1

Okay so your answer would be something like this.

These lines are perpendicular since the slopes are the inverse of one another. The second like would run in the direction of the 4 quadrant. And the first in the direction of the 1st quadrant.
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Answer:

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3 years ago
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Match column a to column b​
solmaris [256]

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2 years ago
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8 0
3 years ago
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Help help help help pls
Monica [59]

Answer:

\theta = 82.2^\circ

Step-by-step explanation:

Let \  \angle BAC = \theta

Opposite = BC ,

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<em><u>Using trigonometric ratios.</u></em>

sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}

Since we have adjacent and hypotenuse we use cosine's  ratio

to find the angle.

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6 0
3 years ago
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