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hram777 [196]
3 years ago
11

Renata moved to her new home a few years ago. Back then, the young oak tree in her back yard was 190 centimeters tall. She measu

red it once a year and found that it grew at a constant rate. 3 years after she moved into the house, the tree was 274 centimeters tall
How fast did the tree grow?

How many years passed from the time Renata moved in until the tree was 344 centimeters tall?
Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
1.

The equation for this problem would be

y = (?)x + 190

With y being the height after a given amount of years and x being the amount of years passing. We would need to find ?, the rate of how fast the tree grows. The problem gives us y = 274 centimeters and x = 3 years

Let’s plug in and solve for ?

274 = ?(3) + 190

84 = ?3

28 = ?

The tree grew 28 cm per year

2.

Since we know the rate of change and y, let’s just plug in values

344 = 28x + 190

154 = 28x

5.5 = x

5.5 years since Renata moved.
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Sari has to read a book for English class by the end of the week she wants to read at least 200 pages in the first 5 days of the
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Henry is giving a 5.5% tip on his bill ,b and his final cost is $60. Which of the following represents that
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2 years ago
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suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio
djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

\mu = \mu_X - \mu_Y = 45 - 35 = 0

\sigma = \sqrt{\sigma_X^2+\sigma_Y^2} = \sqrt{25} = 5

We want to find P(X > 0), that is, 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - 10}{5}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

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4 0
3 years ago
What is the mean ? i don’t need work but it could help
lapo4ka [179]

Answer:

The median is the middle number; found by ordering all data points and picking out the one in the middle.

You want to put the numbers in order:

47, 49, 49, 50, 52, 57, 57, 57, 61

Then you go one number at a time from both ends until you get into the middle:

47, 49, 49, 50, 52, 57, 57, 57, 61

47, 49, 49, 50, 52, 57, 57, 57, 61

47, 49, 49, 50, 52, 57, 57, 57, 61

47, 49, 49, 50, 52, 57, 57, 57, 61

47, 49, 49, 50, 52, 57, 57, 57, 61

So the answer is 52.

Tip: when you do this and you are left with two numbers that are in the middle, add them and divide them by 2.

5 0
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