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IrinaK [193]
3 years ago
5

- Weather happens in the troposphere because it has the highest

Chemistry
1 answer:
Schach [20]3 years ago
6 0
The answer is a. Temperature
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Type the correct answer in the box. Use numerals instead of words.
Murrr4er [49]

Answer:

The amount of energy transferred to the coin is 28.5 joules.







Explanation:

Have a great rest of your day
#TheWizzer

5 0
3 years ago
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Identify three pairs of statements that could be used to start developing a taxonomic key for a mouse, turtle, flamingo, and cat
Zanzabum

Answer:

A dichotomous key is a tool that allows the user to determine the identity of items and organisms in the natural world. ... In each step, the user is presented with two statements based on characteristics of the organism. If the user makes the correct choice every time, the name of the organism will be revealed at the end

Explanation:

4 0
3 years ago
Which is not a type of nuclear decay?<br> A. Zeta<br> B. Gamma<br> C. Alpha<br> D. Beta
IrinaK [193]

Answer:

The answer is Zeta

Explanation:

The three types of nuclear decay are Gamma, Beta, and Alpha.

7 0
3 years ago
Calculate the cell potential E at 25°C for the reaction 2 Al(s) + 3 Fe2+(aq) → 2 Al3+(aq) + 3 Fe(s) given that [Fe 2+] = 0.020 M
Elodia [21]

Answer:

1.18 V

Explanation:

The given cell is:

Al(s)/Al^{3+}(0.10M)||Fe^{2+}(0.020M)/Fe(s)

Half reactions for the given cell follows:

Oxidation half reaction: Al(s)\rightarrow Al^{3+}(0.10M)+2e^-;E^o_{Al^{3+}/Al}=-1.66V

Reduction half reaction: Fe^{2+}(0.020M)+2e^-\rightarrow Fe(s);E^o_{Fe^{2+}/Fe}=-0.45V

Multiply Oxidation half reaction by 2 and Reduction half reaction by 3

Net reaction: 2Al(s)+3Fe^{2+}(0.020M)\rightarrow 2Al^{3+}(0.10M)+3Fe(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.45-(-1.66)=1.21V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Al^{3+}]^2}{[Fe^{2+}]^3}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +1.21 V

n = number of electrons exchanged = 6

Putting values in above equation, we get:

E_{cell}=1.21-\frac{0.059}{6}\times \log(\frac{0.10^2}{0.020^3})\\\\E_{cell}=1.18V

5 0
4 years ago
Glassblower creating sculptures out of glass physical or chemical
ella [17]

Answer:

phsical

Explanation:

it is a phisical cuz your only changing the shape not the chemical structure

5 0
4 years ago
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