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exis [7]
3 years ago
12

Is it true it not possible to transfer the location of energy

Chemistry
1 answer:
lora16 [44]3 years ago
5 0
I would say it is impossible to transfer the location of energy.
You might be interested in
Mg(OH)2+HCl=MgCl2+H2O
attashe74 [19]
Left side:
Mg= 1
O= 2
H= 4
Cl= 2

Right side:
Mg= 1
O= 2
H= 4
Cl= 2
5 0
3 years ago
Please help me with this one true or false
zhenek [66]

Answer:

41. False

42. True

43. False

44. False

45. True

46 - 48. Unsure (I don't take Biology, sorry.)

Explanation:

41.

FeS and HCl are the reactants of the chemical equation. Hence, false.

42.

It is common knowledge that HCl and H₂SO₄ are acids. Hence, true.

43.

Vinegar contains acetic acid CH₃COOH, which isn't a base. Hence, false.

44.

Fluorescence is actually the emittance of light by <em>any substance</em> due to radiation. Hence, false.

45.

Yes, the image produced by a plane mirror is laterally inverted. Hence, true.

3 0
3 years ago
0.05 grams od cobalt ii oxalate will dissolve in one liter of solution at 25 degree celcius. Calculate the ksp for cobalt ii oxa
Veseljchak [2.6K]

Answer:

The equilibrium expression is:

CoC2O4(s)⇌Co2+(aq)+C2O2−4(aq)

For this reaction:

Ksp = [Co2+][C2O2−4]=1.96×10−8

Explanation:

Batteries will not clot if cobalt ions are removed from its cells. Some blood collection tubes contain salts of the oxalate ion,

C2O2−4

, for this purpose. At sufficiently high concentrations, the calcium

and oxalate ions form solid, CoC2O4·H2O (which also contains water bound in the solid). The concentration of Co2+ in a sample of blood serum is 2.2 × 10–3M. What concentration of

C2O2−4

ion must be established before CoC2O4·H2O begins to precipitate.

CoC2O4 does not appear in this expression because it is a solid. Water does not appear because it is the solvent.

Solid CoC2O4 does not begin to form until Q equals Ksp. Because we know Ksp and [Co2+], we can solve for the concentration of

C2O2−4

that is necessary to produce the first trace of solid:

5 0
3 years ago
7. A gas has a volume of 300 mL at 300 mm Hg. What will its volume be if the pressure is changed to 500 mm Hg?​
USPshnik [31]

Answer:

The volume is

<h2>180 mL</h2>

Explanation:

In order to solve for the volume we use the formula for Boyle's law which is

<h3>P _{1}  V _{1} = P _{2}V _{2}</h3>

where

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

Since we are finding the final volume we are finding V2

Making V2 the subject we have

<h3>V _{2}  = \frac{P _{1}  V _{1}}{P _{2}  }</h3>

From the question

P1 = 300 mmHg

V1 = 300 mL

P2 = 500 mmHg

Substitute the values into the above formula and solve for the final volume obtained

That's

<h3>V _{2} =  \frac{300 \times 300}{500}  \\  =  \frac{90000}{500}  \\  =  \frac{900}{5}</h3>

We have the final answer as

<h3>180 mL</h3>

Hope this helps you

7 0
4 years ago
The decomposition of potassium chlorate yields oxygen gas. If the yield is 895%, how many grams of KClO3 are needed to produce 1
harina [27]

The answer is either 38 g or 40.g KCLO3. If it 95% instead of 895%.

4 0
3 years ago
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