Answer:
-5
negative nine-halves
Step-by-step explanation:
we know that
In the quadratic equation
If
then
The system has no real numbers solutions
we have
so
substitute
<u><em>Verify each case</em></u>
case 1) -5
For c=-5
substitute
------> is true
therefore
The value of c=-5 will cause the quadratic equation to have no real number solutions
case 2) negative nine-halves
For c=-9/2
substitute
------> is true
therefore
The value of c=-9/2 will cause the quadratic equation to have no real number solutions
case 3) negative one-quarter
For c=-1/4
substitute
------> is not true
therefore
The value of c=-1/4 will not cause the quadratic equation to have no real number solutions
case 4) 1
For c=1
substitute
------> is not true
therefore
The value of c=1 will not cause the quadratic equation to have no real number solutions
case 5) 9 Over 4
For c=9/4
substitute
------> is not true
therefore
The value of c=9/4 will not cause the quadratic equation to have no real number solutions
Answer:
-4
Step-by-step explanation:
-5 + ______ = -9
-5 + -4 = -9
Answer:
Assume the number is X. What is given can be written as the following:
X < (1/4)*(8X+4)
Multiply 4 on both sides
4X< 8X+4
Subtract 4X+4 from both sides
-4 < 4X
-1<X i.e., X>-1 the number is greater than -1.
your answer is part A ....
Rewritten:
15w^9 - 10w^7 + 12w - 7
Leading coefficient: 15
Degree of the polynomial: 9