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olga55 [171]
4 years ago
15

What is the value of (-14^0)^-2?

Mathematics
2 answers:
il63 [147K]4 years ago
5 0
The value of given expression is 1.
Step-by-step explanation:
The given expression is

If a is a real number, then .
               
Using exponent property we get,
                   


Therefore the value of given expression is 1.
Ainat [17]4 years ago
3 0

Answer:

-6

Step-by-step explanation:

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Pls answer 4 and 5 for brainly
seropon [69]

Number 4 would be: C

And number 5 would be: C

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3 years ago
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(x^-6)^4<br> Someone please help me :)
Anastasy [175]
The answer I came up with was ×^6-4. Just rewrite it. I hope this was helpful.
3 0
3 years ago
What is the area of the triangle?<br> 6<br> 2<br> 3
Llana [10]

Answer:

6

Step-by-step explanation:

Find the area of both triangles inside the bigger triangle and add them together.

Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:

a² + b² = c²

2² + b² = 3²

4 + b² = 9

5 = b²

2.2 ≈ b

Calculate the area of the smaller triangle:

1/2(bxh)

1/2(2 x 2.2)

1/2(4.4)

2.2

Calculate the area of the bigger triangle:

<em>We know that the longer leg is 3.8 units because we were able to subtract the length of the smaller triangle's leg from 6. </em>

1/2(bxh)

1/2(2 x 3.8)

1/2(7.6)

3.8

Add both areas to find the area of the largest triangle:

3.8 + 2.2 = 6

7 0
3 years ago
Dog's video shop rent games for 3 games for $9.99. What is
forsale [732]

Answer:$43.29

Step-by-step explanation:

3 0
3 years ago
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Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
4 years ago
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