Eight hundred seventy six thousand five hundred forty three.
Thats figure is made of 2 triangles and 1 rectangle
so we will find the area of triangles and rectangles then add them
Triangle Area=1/2*x/2*2=x/2
multiply by 2 as we have two triangles=2*x/2=x
Area of a rectangle=x*2=2x
Add them=x+2x=14(given area of trepaziod
3x=14
hope i am correct
It is more than just a quadrilateral. In fact it is going to be hard to pick.
These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.
The converse is "If you have a parallelagram, the diagonals bisect each other."
You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
Answer:
70
Step-by-step explanation:
Opposite Angles are supplementary in cyclic quadratlerials.
