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astraxan [27]
3 years ago
10

Can u help me. where do u plot it. what is x and what is y

Mathematics
2 answers:
goldenfox [79]3 years ago
7 0

Answer:

Step-by-step explanation:

for the first equation x= -2 and y=-7

the second equation x=3 and y is 3 now just plot x and y from the same equation on the same line

Reika [66]3 years ago
3 0

Answer:

\huge\boxed{x = -4; y = 7}

Step-by-step explanation:

By plotting the points, we see that both of the lines intersect at (-4, 7)

Which means (X,y) = (-4,7)

So,

x = -4

y = 7

See the attached file so that you can know how would it be graphed.

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Determine which numbers are solutions for x&gt;7 from the solution set<br> of { 7,8,9}
Vitek1552 [10]

Answer:

8, 9

Step-by-step explanation:

Since x > 7

This means that x cannot equal 7 but must be greater values than 7.

Thus 8 and 9 are solutions

8 0
3 years ago
How would you solve this(what is the equation of the line that passes through the point (3,4) and has a slope of -2/3?)//delta m
andre [41]

Answer:

y = -\frac{2}{3}x + 6

Step-by-step explanation:

y = mx + b is the formula for slope intercept. What we can do is plug in the slope and coordinate points to find the y-intercept.

4 = -\frac{2}{3}(3) + b

-2/3 times 3 is -2 so you can fill that in place.

4 = -2 + b

<u>+2   +2     </u>

6 = b

So the y-intercept is 6 now we can complete the equation.

y = -\frac{2}{3}x + 6

Hope that helps and have a great day!

6 0
3 years ago
За^n(а^n + a^n-1) what is it??
solniwko [45]
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8 0
4 years ago
Helllpppppppppppppppp asap 22 pts
Rama09 [41]
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5 0
3 years ago
0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?
MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So,  4# · 3# · 2# · 1#? =  6912 · 24 · 2 · 1? = 331776

7 0
3 years ago
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