Standard deviation (s): 2.7386127875258
The coefficient of y∧15×∧2 in expansion of (y∧3+x)∧7 is (15×2)+(3×7)= 51
Answer:
its 4/64
if u want to simplfy its 1/16 :)
Step-by-step explanation:
i promise i did the math
Bring the 13 over to read
13-12y-13=0
then move the 12y over do it becomes
13-13=12y
0=12y
y=0
W=148
V=180-148=32
V=32
T=148
S=148
Yes, it is correct