ABCD is a square. What is the measure of angle BAC?
2 answers:
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The area can be found as the magnitude of the cross product of the vectors representing two adjacent sides.
area = || kl × kn || = || (0, 2, 1) × (4, 5, 0) ||
= || (-5, 4, -8) || = √105
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For the purpose here, kl = l - k = (1, 3, 2) - (1, 1, 1) = (0, 2, 1)
and nk = n - k = (5, 6, 1) - (1, 1, 1) = (4, 5, 0)
The cross product can be calculated using a suitable calculator. By hand, it is the determinant
where i, j, k are unit vectors in the x, y, z directions.
area = || kl × kn || = || (0, 2, 1) × (4, 5, 0) ||
= || (-5, 4, -8) || = √105
_____
For the purpose here, kl = l - k = (1, 3, 2) - (1, 1, 1) = (0, 2, 1)
and nk = n - k = (5, 6, 1) - (1, 1, 1) = (4, 5, 0)
The cross product can be calculated using a suitable calculator. By hand, it is the determinant
where i, j, k are unit vectors in the x, y, z directions.
Given equation is
It can be written as follows.
Which is of the form
where a=3 and b=4.
We know that the coordinates of the vertices are (a,0) and (-a,0)
Substitute a=3, we get
The vertices are (3,0) and (-3,0).
We know that the coordinates of the foci are (c,0) and (-c,0)
Substitute a=3 and b=4, we get
Substitute c=5, we get
Hence the foci are (5,0) and (-5,0).