All categories

3 years ago

To convert from a smaller unit to a larger unit, you _____ by a power of ten

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

5 0

You would need to multiply my ten

horrorfan [7]3 years ago

3 0

You would need to multiply it by ten

You might be interested in

Estimate a line of best fit using two points on the line

olga55 [171]

Your answer is A.

y = -1/2x + 9

3 0

3 years ago

Read 2 more answers

I need help please on this question

Aleks [24]

Answer:

Step-by-step explanation:

3 0

3 years ago

One third of a birds eggs hatched if 2 eggs hatched, how many eggs did the bird lay.

irinina [24]

Answer:

6 eggs

Step-by-step explanation:

given

one third (i.e 1/3 ) ---> equivalent to 2 eggs

total number of eggs

= three-thirds

= 3 x (1/3) -----------> equivalent to 3 x 2 eggs = 6 eggs

4 0

2 years ago

¿Cuál es el área de un rectángulo, sabiendo que su perímetro mide 24 cm y que su base es el triple de su altura?

Brrunno [24]

Answer:

El área del rectángulo es:

27 cm²

Step-by-step explanation:

Consideración:

La formula del perímetro de un rectángulo es:

p = 2(altura + base)

Planteamiento:

24 = 2(a+b)

b = 3a

a = longitud de la altura del rectángulo

b = longitud de la base del rectángulo

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

24 = 2(a + 3a)

24/2 = 4a

12 = 4a

a = 12/4

a = 3 cm

de la segunda ecuación del planteamiento:

b = 3a

b = 3*3

b = 9 cm

Comprobación:

de la primer ecuación del planteamiento:

24 = 2(3+9)

24 = 2*12

Respuesta:

la formula del área de un rectángulo es:

A = base * altura

A = 9cn * 3cm

A = 27cm²

5 0

3 years ago

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

3 years ago

Read 2 more answers