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2 years ago

What is the coefficients of x² in (2-3x) (x²-5)

Mathematics

2 answers:

aniked [119]2 years ago

5 0

Answer:

Step-by-step explanation:

=> $(2-3x)(x^2-5)$

=> $(2x^2-10-3x^3+15x)$

Arranging it in descending order

=> $-3x^2+2x^2+15x-10$

So, the coefficient of x² in this expression is +2

SOVA2 [1]2 years ago

3 0

This depends if you are supposed to simplify the binomials first:

If you leave it in the form provided then the coefficient would be 1

However, you can multiply the binomials together in order to simplify the expression:

$(2 - 3x)( {x}^{2} - 5)$

$(2 \times {x}^{2} ) + (2 \times - 5) + ( - 3x \times {x}^{2} ) + ( - 3x \times - 5)$

${ - 3x}^{3} + {2x}^{2} + 15x - 10$

Which then shows the coefficient would be 2

So it all depends on the directions provided, I would assume the correct answer is 2 if the directions are the exact same as provided on Brainly.

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2 years ago

Write equation of the line containing (6,3) and (4,1) Group of answer choices y = -1x + 5 y = 1x - 3 y = 1x + 5 y = -1x + 3

Natalka [10]

Answer:

y = x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (6, 3) and (x₂, y₂ ) = (4, 1)

m = $\frac{1-3}{4-6}$ = $\frac{-2}{-2}$ = 1 , then

y = x + c ← is the partial equation

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Using (4, 1 )

1 = 4 + c ⇒ c = 1 - 4 = - 3

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3 years ago

4. Consider all possible rectangular solids defined by 0 ≤ x ≤ a, 0 ≤ y ≤ b, 0 ≤ z ≤ 1 and the vector field given by F = (−x 2 −

N76 [4]

Step-by-step explanation:

By using the Divergence Theorem, the flux equals

∫∫∫ div F dV

= ∫∫∫ ((-2x - 4y) + (-6z) + 12) dV

= ∫(z = 0 to c) ∫(y = 0 to b) ∫(x = 0 to a) (12 - 2x - 4y - 6z) dz dy dx

= ∫(z = 0 to c) ∫(y = 0 to b) (12a - a^2 - 4ay - 6az) dy dx

= ∫(z = 0 to c) (12ab - a^2 b - 2ab^2 - 6abz) dx

= 12abc - a^2 bc - 2ab^2 c - 3abc^2.

So, we need to find the maximum value of

f(a,b,c) = 12abc - a^2 bc - 2ab^2 c - 3abc^2, with a,b,c > 0.

First, we find the critical points of f.

f_a = 12bc - 2abc - 2b^2 c - 3bc^2 = bc(12 - 2a - 2b - 3c)

f_b = 12ac - a^2 c - 4abc - 3ac^2 = ac(12 - a - 4b - 3c)

f_c = 12ab - a^2 b - 2ab^2 - 6abc = ab (12 - a - 2b - 6c).

Setting these equal to 0 (and remembering that a, b, c > 0):

12 - 2a - 2b - 3c = 0

12 - a - 4b - 3c = 0

12 - a - 2b - 6c = 0

Solving this system yields a = 3, b = 3/2, c = 1.

By the Second Derivative Test or otherwise, this can easily be checked to yield the maximum flux.

This maximal flux equals f(3, 3/2, 1) = 27/2

7 0

2 years ago

What is the coefficients of x² in (2-3x) (x²-5)​

What is the coefficients of x² in (2-3x) (x²-5)