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Virty [35]
3 years ago
6

If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​

bgg, gbb,​ gbg, ggb, ggg.
a. construct a similar sample space for the possible weightweight outcomes​ (using o for overweight and u for underweighto for overweight and u for underweight​) of two children.
b. assuming that the outcomes listed in part​ (a) were equally​ likely, find the probability of getting two underweightunderweight children.
c. find the probability of getting exactly one overweightoverweight
Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0
There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU

There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4

The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2

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siniylev [52]

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Answer:

  6 feet

Step-by-step explanation:

The volume of a cylinder is given by ...

  V = πr^2·h

For a sphere, the volume is ...

  V = 4/3πr^3

You want the volumes to be the same when h=8, so we have ...

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Dividing by πr^2, we have ...

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The radius is 6 feet.

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saw5 [17]

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aev [14]
I would say B . 
They are not like terms because they are not all the same
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sergij07 [2.7K]
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Of means multiply
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Or you can use another way which is (part/whole) *(percent/100)

Whole=65
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