Answer:
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
Step-by-step explanation:
<u>Explanation:</u>
Given data a survey of an urban university (population of 25,450) showed that 883 of 1,112 students sampled supported a fee increase to fund improvements to the student recreation center.
Given sample size 'n' = 1112
Sample proportion 'p' = 
q = 1 - p = 1- 0.7940 = 0.206
<u>The 95% level of confidence intervals</u>
The confidence interval for the proportion of students supporting the fee increase

The Z-score at 95% level of significance =1.96

(0.7940-0.02376 , 0.7940+0.02376)
( 0.77024, 0.81776)
<u>Conclusion:</u>-
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
11t=120(12)
11t=1440
t=1440/11
However t is in hours and we want to know days so:
d=(1440/11)/24
d=1440/264
d=60/11
d=5 5/11 days
Answer:
The answer is AAS.
Step-by-step explanation:
Since you have 2 angles that are the same and 1 side which are the same or congruent.
A = E
and C=C they are vertical angles so they are the same
And the AB and ED side are also same.
F(x) = 1 / (x - 2)...when x = 4
f(4) = 1 / (4 - 2)
f(4) = 1/2 <==
f(x) = 1 / (x - 2)...when f(x) = 1
1 = 1 / (x - 2) ...multiply both sides by (x - 2) eliminating it on the right
1(x - 2) = 1
x - 2 = 1
x = 1 + 2
x = 3 <==
Answer:
Lisa must get an 88.75 or higher to stay in between 80 and 90.
Step-by-step explanation: