Answer:
Step-by-step explanation:
sin 52 cos 13-cos 52 sin 13=sin (52-13)=sin 39
<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal
to the x-coordinate of the vertex. </span>
<span>Note that a quadratic
equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at
h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>
Answer:
arc AB = 70°
arc BC = 110°
arc ABC = 180°
arc CDB = 250°
Step-by-step explanation:
Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.
Solve for arc AB:
Angle AFB = 70°, so arc AB = 70°
Solve for arc BC:
Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.
180 - 70 = 110°
Since angle BFC = 110°, arc BC = 110°
Solve for arc ABC:
Add arc AB and arc BC together.
70° + 110° = 180°
arc ABC = 180°
Solve for arc CDB:
There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.
360° - 110° = 250°
arc CDB = 250°